Question

A force of of 1200 n and
Act on the surface of area 10 cm2 normally what would thrust and pressure on the surface

Answer 1

1.2 x 10^6 N / m^2

Given:

Force = 1,200 Newtons

Area = 10 cm^2

Converting the area in meters we get:

= 10 ×10^-4 m^2

= 10^-3 m^2

To Find:

Thrust and Pressure that is there on the surface.

Calculating:

The thrust is equal to the force as thrust is normal pressure.

Therefore, the thrust that is there on the surface is 1,200 Newtons.

Formula that is used to calculate pressure:

Pressure = Force / Area

Substituting the values known to us in this formula we get:

= 1200 N / 10^−3 m^2

We can write 1200 Newtons as 1.2 x 10^3:

= 1.2 x 10^3 N / 10^-3 m^2

Taking 10^-3 to the numerator we get:

= 1.2 x 10^3 N x 10^3 / m^2

= 1.2 x 10^3 + 3 / m^2

= 1.2 x 10^6  N / m^2

Therefore, the pressure is 1.2 x 10^6 N / m^2.

Answer 2

$\huge{ \underline{ \underline \purple{ \mathfrak{Given}}}}$

• Force (F) = 1200N
• Area. (A) = 10m²

$\huge {\underline{ \underline \purple{ \mathfrak{To \: Find}}}}$

• Pressure (P)

$\huge{ \underline {\underline \purple {\mathfrak{Solution}}}}$

We know that,

→ Pressure × Area = Force

→ P × A = F

So,

→ P × 10 = 1200

→ P = 1200/10

→ P = 120N/m² or Pascal's

Hence,

${\fcolorbox{red}{blue}{\underline{ \underline Pressure = 120 \: pascals}}}$