Question

. A force of one newton doubles the length of a cord having cross-sectional area 1 mm2. The Young's modulus of the material of cord is :

Answer 1

Explanation:

Force(F)=1N, Area(A)=1mm²=${10}^{ - 6}$,

Initial length=L,

Change in length(∆L)=2L

Y =(F/A)/(∆L/L)

Y = (1/${10}^{ - 6}$)/(2)

Y = 0.5 × ${10}^{6}$

Answer 2

Here is ur answer...

Plz mark me as brainliest...