A force of p=3mg acts on a block of mass m at an angle of 30 with the horizontal. The friction force between the block and ground (assuming u=coefficient of friction between the contacting surface) is
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Explanation:
According to the problem
the mass of the block is m and making angle of 30 ° horizontally
therefore,
According to the figure
the vertical component of the force is psinθ= 3mgsin(30°)
= 1.5 mg
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