Question

a force of two ICAP - 4 j cap + 2 k cap Newton acts at a point 3 ICAP + 2 J cap - 4 k cap metre from the origin the magnitude of torque is​

Answer 1

Answer: The torque is -52i-34j-16k.

Explanation:

Please refer to the attachment below. Hope it helps.

Answer 2

The magnitude of torque due to this force is 24.41 N-m.

Explanation:

It is given that,

Force acting on the particle, $F=(2i-4j+2k)\ N$

Position of particle, $r=(3i+2j-4k)\ m$

We need to find the magnitude of torque. It is given by the product of force and position.

$\tau=F\times r$

$\tau=(2i-4j+2k)\times (3i+2j-4k)$

On taking the cross product of above quantities, we get the value of torque vector is as follows :

$\tau=(12i+14j+16k)\ Nm$

Magnitude of torque,

$|\tau|=\sqrt{12^2+14^2+16^2}$

$|\tau|=24.41\ Nm$

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