A force on a particle of 200g displaces it through a distance of 400cms in 2 seconds. If the particle is initially at rest then the magnitude of force is?
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Answered by
30
Given:
mass=m=200g=0.2kg
distance=s=400cm=4m
time=t=2 sec
u=0 m/s
find F?
By second law of motion,
S=ut+1/2 at²
⇒⇒0 +1/2x a x4=4
⇒a=2 m/s²
By second equation of motion,
F=ma
⇒⇒0.2 x 2 =0.4N
∴ Magnitude of Force is 0.2N
mass=m=200g=0.2kg
distance=s=400cm=4m
time=t=2 sec
u=0 m/s
find F?
By second law of motion,
S=ut+1/2 at²
⇒⇒0 +1/2x a x4=4
⇒a=2 m/s²
By second equation of motion,
F=ma
⇒⇒0.2 x 2 =0.4N
∴ Magnitude of Force is 0.2N
Answered by
2
Answer:
0.2N
Explanation:
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