Question

A force on body of mass 0.4kg initialy at rest for 10sec. After removal of force, if body moves 100m in 20sec, the force on that body is?

Answer 1

S=100m, time=20s now v=S/t=5m/s

Now, F=m(v-u)/t=m(5/20)= m*1/4= 4/10*1/4=1/10N