a force on particle of 200g displaces it through a distance of 400cm in 2s if the particle is initially at rest then magnitudeof force will be
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F = ma
m = 200/1000 = 0.2 kg
a = ΔV/Δt = 4/2 = 2m/s^2
F = 0.2 * 2
F = 0.4 N
Hope it helped you
m = 200/1000 = 0.2 kg
a = ΔV/Δt = 4/2 = 2m/s^2
F = 0.2 * 2
F = 0.4 N
Hope it helped you
chinmay97:
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Answer:
the answer is 0.4N
Explanation:
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