Physics, asked by sunithajakkena, 6 months ago

A force \overline{\mathbf{F}}=(5 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}) \mathbf{N} F =(5 i ^ −3 j ^ ​ +2 k ^ )N moves a particle from \overline{\mathbf{r}}_{1}=(\mathbf{2} \hat{\mathbf{i}}+7 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}) \mathbf{m} r 1 ​ =(2 i ^ +7 j ^ ​ +4 k ^ )m to \overline{\mathbf{r}}_{2}=(5 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}+8 \hat{\mathbf{k}}) \mathbf{m} r 2 ​ =(5 i ^ +2 j ^ ​ +8 k ^ )m The work done by the force is....(in joules)

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Answered by samiaiman343
1

Answer:

What is your question............

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