A force p=3i+4j-5k unit is applied on a particle at the origin. as a result the particle moves to the point (2,-3,-6).the work done on the particle
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Answer: 24 joules
Explanation:W = F.d
= (3i +4j - 5k). (2i - 3j - 6k) = 6-12 + 30 = 24 joules
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