A force p=3mg acts on a block of mass m at an angle of 30 with horizontal. The friction force between the block and ground is
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According to the problem
the mass of the block is m and making angle of 30 ° horizontally
therefore,
According to the figure
the vertical component of the force is psinθ= 3mgsin(30°)
= 1.5 mg
The resultant force will be 1.5mg-mg=0.5 mg vertically upwards
As the force is acting upwards from the ground therefore there is no interaction between the block and the ground
Therefore the frictional force is zero
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