Question

A force p=3mg acts on a block of mass m at an angle of 30 with horizontal. The friction force between the block and ground is

Answer 1

Answer:

According to the problem

the mass of the block is m and making angle of 30 ° horizontally

therefore,

According to the figure

the vertical component of the force is psinθ= 3mgsin(30°)

= 1.5 mg

The resultant force will be 1.5mg-mg=0.5 mg vertically upwards

As the force is acting upwards from the ground therefore there is no interaction between the block and the ground

Therefore the frictional force is zero