) A force P is directed from a point A (4, 1, 4) meters towards a point (-3, 4,-1) meters. If it cause
a moment of MZ=9000Nm, determine the moment of P about the x-and y-axes.
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Step-by-step explanation:Moment of a force is equals to force times perpendicular distance .
Moment of MZ = 90000Nm means the constant force time change in distance along z.
Therefore 9000 = F (4-(-1)) ; 9000 = F(5)
The constant force = 1800N
We're asked to find the moment of P about x-axis: to find that, we'd need to multiply the constant force by change in distance along x axis.
Therefore moment of P about x-axis = 1800(7)= 12600Nm. Where 7 denote change in distance along x-axis.
Same method applies to moment of P about y-axis
Moment of P about y-axis = 1800(3)= 5400Nm.
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