Question

a force P of 235 Newton act on angle 60 degree with the horizontal resting on a 22 degree inciled plane as shown in figure..

1)px
2)py

Answer 1

Hey.

1) Px= Pcos(60+22)=235×cos82=235×0.139= 32.71 N
2) Py= Psin82=235×sin82=235×0.99=232.71 N

Thanks.

Answer 2

Answer: Force in the horizontal direction $P_x = 32.71N$ the same in the vertical direction $P_y = 232.71N$

Force: The ability to push or pull objects. It is a vector quantity. Its SI unit is Newton (N).

Step-by-step explanation:

Step 1: Given Data

The angle of incline θ = 22°

The angle of Force from the Horizontal as per the diagram Ф = 60°

Net Force on the body = 235N

Step 2: Angle of Net Force from the horizontal α

We can see clearly from the given diagram α = θ + Ф  

α = 22°+60° = 82°

α = 82°

Step 3: Find $P_x \hspace{4}and\hspace{4} P_y$

$P_x = Pcos\alpha \\P_x = Pcos82 = 235 X 0.139 =32.71N$

Similarly,

$P_y = Psin\alpha \\P_y = Psin82\\P_y = 235X0.99=232.71N$

Therefore, Force in the horizontal direction $P_x = 32.71N$ the same in the vertical direction $P_y = 232.71N$