Question

A force produces an acceleration of 5ms/2 when applied on a body of mass 4kg the magnitude of the force applied is?​

Answer 1

Answer:

A force produces an acceleration of 5ms/2 when applied on a body of mass 4kg. The magnitude of the force applied will be $20 N$.

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Explanation:

We can solve this question by using Newton's second law of motion.

According to Newton's second law, the force applied will be equivalent to the product of the mass of the object and its acceleration.

That is,

$Force (F) = mass(m)\times acceleration(a)$

In the question, it is given that,

$m = 4\ kg$

$a = 5\ m / s^{2}$

Substitute these values into the above equation,

$F = 5\times 4 = 20 \ N$

So,

The magnitude of force applied = $20\ N$

Answer 2

Answer:

Given :-

• A force produces an acceleration of 5 m/s² when applied on a body of mass 4 kg.

To Find :-

• What is the magnitude of the force applied.

Formula Used :-

$\clubsuit$ Force Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{F =\: ma}}}\: \: \: \bigstar$

where,

• F = Force (N)
• m = Mass (kg)
• a = Acceleration (m/s²)

Solution :-

Given :

• Mass = 4 kg
• Acceleration = 5 m/s²

According to the question by using the formula we get,

$\implies \sf\bold{\purple{F =\: ma}}$

$\implies \bf Force =\: Mass \times Acceleration$

$\implies \sf Force =\: 4 \times 5$

$\implies \sf\bold{\red{Force =\: 20\: N}}$

$\therefore$ The magnitude of the force applied is 20 Newton .