Question

A force $\vec{F}=(5\hat{i}+3\hat{j}+2\hat{k})N$ is applied over a particle which displaces it from its origin to the point$\vec{r}=(2\hat{i}-\hat{j})m$. The work done on the particle in joule is(a) +10 (b) +7(c) –7 (d) +13

Answer 1

sry I don't know I am sry

Answer 2

Hey superstar here is your soln:

Work done=force.distance

Here . means dot product

So W=(5i+3j+2k).(2i-j)= 7J

Hope this will help you

Pls mark it as brainliest