Question

A force vec(F)=4hati-10 hatj acts on a body at a point having position vector -5hati-3hatj relative to origin of co-ordinates on the axis of rotation. The torque acting on the body is

Answer 1

Answer:

Force acting on the body   F=4i^−10j^

Position vector   r=−5i^−3j^

Thus, torque   τ=r×F

$$\implies \ \vec{\tau} =(-5\hat{i} - 3\hat{j})\times (4\hat{i}  - 10\hat{j}) = 62\hat{k}$$