Question

A force \vec f = 5 \hat i - 4 \hat j +\hat k moves a body of mass 10 kg from position (3,4,5) to a position (6,7,8) . Find the work done

Answer 1

Answer:

displacement =(6i+7j+7k)-(3i+4j+5k)

d=(3i+3j+3k)

so work done

w=F.d

=(5i-4j+k).(3i+3j+3k)

=15-12+3

=6 joule