Question

A force \vec{F}=(6 \hat{i}+3 \hat{j}-4 \hat{k}) NF=(6i^+3j^​−4k^)N acts on a particle which is constrained to move in the XOY plane along the line x=y .x=y. If the particle moves 5 \sqrt{2} m,52​m, the work done by force in joule is
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Answer 1

Refer the above attachment

Refer the above attachmentHope it helps you........

Answer 2

Answer:

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