A force vector f=2i+3j+k act on a body find the work done by the force for a displacement of-2i+j-k
Answers
Answered by
4
The magnitude of the force is :
√2² + 3² + 1² = √14 = 3.742
Magnitude of the distance is :
√(-2)² + 1² + (-1)²
√6 = 2.449
Work done = Force × Distance
Work = 2.449 × 3.742 = 9.164 Unit Joules
Answered by
4
Answer:
9.164 joules bro
Explanation:
- magnitude of f= √2²+3²1²= √14
- magnit of distanc is √6=2.449
- W= 9.164 j
Similar questions