Question

A force vector f=2i+3j+k act on a body find the work done by the force for a displacement of-2i+j-k

Answer 1

The magnitude of the force is :

√2² + 3² + 1² = √14 = 3.742

Magnitude of the distance is :

√(-2)² + 1² + (-1)²

√6 = 2.449

Work done = Force × Distance

Work = 2.449 × 3.742 = 9.164 Unit Joules

Answer 2

Answer:

9.164 joules bro

Explanation:

• magnitude of f= √2²+3²1²= √14
• magnit of distanc is √6=2.449
• W= 9.164 j