Question

a force vector f is equal to 5 ICAP + 3 J cap newton is applied over a particle which displaces it from its origin to the point vector are equal to two ICAP - 1 J cap metre the work done on the particle is​

Answer 1

The net work done on the particle is 7 joules .

Answer 2

The work done on the particle is 2 Joules.

Explanation:

Given that,

Force, $F=5i+3j$

Position, $r=i-j$

Let W is the work done on the particle. It can be calculated using the dot product of force and displacement.

$W=F{\cdot}r$

$W=(5i+3j){\cdot}(i-j)$

W = 5 - 3

W = 2 J

So, the work done on the particle is 2 J.

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Topic : Work done and displacement

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