A force was applied over a mass of 40 kg by which its velocity becomes 5 m/s from 2 m/s. Find the magnitude of work done by force applied
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according to work energy conversion theorem
work done by the force =change in kinetic energy
work done by the force =1/2m(v2-u2)
here mass =40kg
final velocity =5m/s
initial velocity =2m/s
work done =1/2*40(25-4)
=1/2*40*21
=20*21
=420joule
hope it helps you
work done by the force =change in kinetic energy
work done by the force =1/2m(v2-u2)
here mass =40kg
final velocity =5m/s
initial velocity =2m/s
work done =1/2*40(25-4)
=1/2*40*21
=20*21
=420joule
hope it helps you
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