Question

A forester measures a 34 degree angle of elevation for a tree in sequoia national park. When the forester moved 300 feet further away, the angle of elevation was 20 degrees. How tall was the tree

Answer 1

Answer:

235.6 feet

Step-by-step explanation:

Tan34=L/A

.6745=L/A

L=.6745A -----(1)

Tan20=L/(A+300)

.3639=L/(A+300)

L=(.3639A+109.191) -----(2)

using (1) & (2)

.6765A=.3639A+109.191

.3126A=109.191

A=349.3

put A's value in (1)

L=(.6745*349.3)

L= 235.6