Question

A forester wants to plant 66 apple trees, 88 banana trees and 110 mango trees in equal rows (in terms of number of trees). Also he wants to make distinct rows of trees (i.e., only one type of trees in one row). The number of minimum rows required are (a) 2(b) 3(c) 10(d) 12​

Answer 1

Answer:

(D) 12

Step-by-step explanation:

The prime factorization of 66 is

⇒66=2×3×11

The prime factorization of 88 is,

⇒88=2×2×2×11

The prime factorization of 110 is,

⇒110=2×5×11

Since 2×11 is common in the prime factorization of all numbers. So,

⇒HCF=2×11=22

Thus, the number of trees in each row will be 22 trees.

Now, find the total number of trees,

⇒ Total trees =66+88+110

Add the terms,

⇒ Total trees =264

Now, divide the total number of trees by trees in each row to find the number of rows required,

⇒ Total number of rows =264/22

Cancel out the common factors,

∴ Total number of rows =12