Question

A fork A vibrates with a frequency of 320 Hz and is

placed just by the side of B whose frequency is 360 Hz.

Then B begins to vibrate with a frequency of​

Answer 1

Answer:

Given,

Frequency=200Hz

Speed of sound =330m/s

Number of vibrations=20

therefore,Time period=

frequency

1

=

200

1

=0.005sec

Total time= Time period × number of vibrations

=0.005×20=0.1sec

Now,

Distance travelled= Speed × time

=330×0.1=33m