Question

a former counts 9 heads and 24 legs of chickens and cows how many have each of them chicken and cows

Answer 1

Solution:-
Let 'x' be the total number of chickens and 'y' be the total number of cows and each has 1 head.
So,
x + y = 9 .......(1)
Each chicken has 2 legs and each cow has 4 legs.
So,
2x + 4y = 24 .........(2)
Now, multiplying the equation (1) by 2, we get
2x + 2y = 18 
and then subtracting this from equation (2),

  2x + 4y = 24
  2x + 2y = 18
 -     -        -
____________
        2y  = 6
____________
y = 3
So, the number of cows is 3.
Putting the value of y = 3 in equation (1), we get
x + 3 = 9
x = 9 - 3 
x = 6
So, the number of chickens is 6.
Answer.