Question

A formula one race car accelerates with a speed of 105 km/h in the first 15 minutes and then moves at 212 km/h in the next 20 minutes, find the distance traveled by the car

Answer 1

Initial speed = u = 105km/h in m/s = 105x5/18 m/ s = 29.16m/s

final speed = v = 212km/h in m/s = 212x5/18 m/s = 58.89m/s

intial time = t1 = 15 x 60 = 90s

final time = t2 = 20 x 60 = 120s

total distance = s = ?

1. distance = speed ×time

then d1 = u× t1 (initial speed)×t1...distance travelled in 1st case

2. distance = speed × time

then, d2= v×t2 .distance traveled in second case)

S(total distance)= ut1 + vt2

S= 29.16(90) + 58.89(120) S= 2624.4 + 7066.8

S= 9691.2 meter.... ...ans..