A formula one race car accelerates with a speed of 105 km/h in the first 15 minutes and then moves at 212 km/h in the next 20 minutes find the distance travelled by the car
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Initial speed = u = 105km/h = 105×5/18 m/s = 29.16m/s
final speed = v = 212km/h = 212×5/18 m/s = 58.89m/s
intial time = t1 = 15 × 60 = 90s
final time = t2 = 20 × 60 = 120s
total distance = s = ?
u = d/t1 (distance traveled in first case)
d1 = ut1
v = d/t2 (distance traveled in second case)
d2= vt2 .
S = d1 + d2
S = ut1 + vt2
S = 29.16(90) + 58.89(120)
S = 2624.4 + 7066.8
S = 9691.2 meter
final speed = v = 212km/h = 212×5/18 m/s = 58.89m/s
intial time = t1 = 15 × 60 = 90s
final time = t2 = 20 × 60 = 120s
total distance = s = ?
u = d/t1 (distance traveled in first case)
d1 = ut1
v = d/t2 (distance traveled in second case)
d2= vt2 .
S = d1 + d2
S = ut1 + vt2
S = 29.16(90) + 58.89(120)
S = 2624.4 + 7066.8
S = 9691.2 meter
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