A fort had a provision for 450 soldiers for 80 days. After 10 days, 50 more soldiers come to the
fort. Find for how many days will the remaining provisions last at the same rate?
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No. of men at the beginning =450
No. of men arrived after 10 days =50
Total Number of mens after 10 days =450+50=500
Total . of days =80
After 10 days, period =70 days
After 10 days, there will be 500 mens
Let x be the no. of days till which the food remains
∴450:500=70:x
By inverse proportion,
500:450=70:x
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