Math, asked by Anonymous, 3 months ago

A fort has provisions for 300 men for 90 days . After 20 days , 50 men left the fort . How long would the food last at the same rate ?

Answers

Answered by tanunagar21
3

Answer:

84

Step-by-step explanation:

Remaining number of men =(300−50)=250.

Remaining number of days =(90−20)days=70 days

300 men had provisions for 70 days

1 man had provisions for (300×70) days ...[less men, more days]

250 men had provisions for

250

300×70

days =84 days ...[more men, less days]

Hence, the remaining food will last for 84 days.

Answered by jayajayarani
0

Step-by-step explanation:

Remaining number of men =(300−50)=250. 

Remaining number of days =(90−20)days=70 days 

300 men had provisions for 70 days 

1 man had provisions for (300×70) days         ...[less men, more days]

250 men had provisions for 250300×70 days  =84 days           ...[more men, less days] 

Hence, the remaining food will last for 84 days. 

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