A forward potential of 10V is applied to a Si diode. A resistance of 1 KΩ is also in series with the diode. Find the current.
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The voltage drop across a Si diode under forward bias conditions is taken to be its cutin voltage of 0.7 Volt, if we use the idea of linear piecewise modelling of diodes.
In that scneario, considering the forward-biased diode to be approximated by simply a 0.7 V battery, the current through the circuit having 1 KOhm resistor becomes (10-0.7)/1 mA, which is 9.3 mA.
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If we adopt the notion of linear piecewise modelling of diodes, the voltage drop across a Si diode under forward bias circumstances is considered to represent its cutin voltage of 0.7 Volt.
In that case, the current through the circuit with the 1 KOhm resistor becomes (10-0.7)/1 mA, or 9.3 mA, when the forward-biased diode is represented by a 0.7 V battery.
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