A forward potential of 10V is
applied to a Si diode. A resistance
of 1 KQ is also in series with the
diode. The current is
Options
A
10 mA
B
1 mA
C
0.7 mA
Answers
Answered by
0
Answer:
Option B 1mA
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Answered by
1
Answer:
The voltage drop across a Si diode under forward bias conditions is taken to be its cutin voltage of 0.7 Volt, if we use the idea of linear piecewise modelling of diodes.
In that scneario, considering the forward-biased diode to be approximated by simply a 0.7 V battery, the current through the circuit having 1 KOhm resistor becomes (10-0.7)/1 mA, which is 9.3 mA.
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