a fountain is enclosed by a circular fence of circum ferance 11m and is surrounded by a circular path the circumferance of the outer bountary of the path is 16 m
Answers
Diameter of the circular garden=21m
∴ Radius of the circular garden=
2
21
m
Now, circumference of circular garden=2πr=2×
7
22
×
2
21
=22×3=66m
The gardener makes 2 rounds of fence so the total length of the rope of fencing =2×2πr=2×66=132m
Since the cost of 1 meter rope=Rs. 4
Therefore, cost of 132 meter rope=4× 132=Rs. 528.
Hope it is help for you
Answer:
Step-by-step explanation:
CIRCUMFERENCE OF INNER CIRCLE OF PATH = 220/7m
AREA OF THE PATH = 528/7m²
Step-by-step explanation:
A circular pond is surrounded by a 2m wide circular path
OBJECTIVE
1) Find the area of the path.
2) Inner circumference of the circular path.
RADIUS OF THE OUTER CIRCUMFERENCE OF THE PATH
Circumference = 2πr
44m = 2πr
44m = 2*22/7*r
44m = 44/7*r
r = 44*7/44m
r = 7m
RADIUS OF INNER CIRCUMFERENCE OF THE PATH:
Radius of outer circumference of the path - 2m
= 7m - 2m
= 5m
CIRCUMFERENCE OF INNER CIRCLE OF THE PATH
Circumference = 2πr
Circumference = 2*22/7*5m
Circumference = 44/7*5m
Circumference = 220/7m
AREA OF THE POND
Area = πr²
Area = 22/7*5²m²
Area = 22/7*25m²
Area = 550/7m²
AREA OF THE WHOLE CIRCLE
Area = πr²
Area = 22/7*7²m²
Area = 22/7*49m²
Area = 154m²
AREA OF THE PATH
=Area of the whole circle - Area of the pond
=154m²-550/7m²
=1078m²-550m²/7
=528/7m²