Question

A four digit number 2652 is such that any two consecutive digit from it is multiple of 13. another number n having 100 digits has same property and begins with 9. the last digit of n is

Answer 1

Answer:

9

Step-by-step explanation:

The two-digit multiples of 13 are

13, 26, 39, 52, 65, 78, 91.

N starts with a 9, so the first two digits must be 91. Then the second and third must be 13, and the third and fourth 39.

Then the sequence repeats, so N is 913913913...913 up to the 99th digit, with 9 as its 100th digit.

Hence the answer is 9......

Answer 2

answer is 9

Step-by-step explanation:

913913913.....(100 digits)

we see that 913 is repeated. 913 comes 33 times so the last digit will be 9