Math, asked by shristigupta9945, 11 months ago

A four digit number 4ab5 is divisible by 55 Them determine the value of b-a

Answers

Answered by vipinchauhan6522
3

Answer:

difference is 1

Step-by-step explanation:

if we take A=1 ,B=2

then it becomes 4125 which is divisible by

55.

Answered by TanikaWaddle
3

The value of b-a = 1

Step-by-step explanation:

In a number 4ab5

the last digit is 5 , therefore it is divisible by 5

55 = 11× 5

so , the number is also divisible by 11

then the sum of its odd and even terms must be divisible by 11

4+b-(a+5)=a number divisible by 11

b-a = a number divisible by 11 +1

since , a and b are single number digits hence , it satisfies only 0

therefore, b-a = 1

#Learn more :

Which is true about the completely simplified difference of the polynomials a3b + 9a2b2 − 4ab5 and a3b − 3a2b2 + ab5? The difference is a binomial with a degree of 5.

https://brainly.com/question/1128299

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