A four digit number 4ab5 is divisible by 55 Them determine the value of b-a
Answers
Answered by
3
Answer:
difference is 1
Step-by-step explanation:
if we take A=1 ,B=2
then it becomes 4125 which is divisible by
55.
Answered by
3
The value of b-a = 1
Step-by-step explanation:
In a number 4ab5
the last digit is 5 , therefore it is divisible by 5
55 = 11× 5
so , the number is also divisible by 11
then the sum of its odd and even terms must be divisible by 11
4+b-(a+5)=a number divisible by 11
b-a = a number divisible by 11 +1
since , a and b are single number digits hence , it satisfies only 0
therefore, b-a = 1
#Learn more :
Which is true about the completely simplified difference of the polynomials a3b + 9a2b2 − 4ab5 and a3b − 3a2b2 + ab5? The difference is a binomial with a degree of 5.
https://brainly.com/question/1128299
Similar questions
India Languages,
5 months ago
English,
5 months ago
Math,
5 months ago
CBSE BOARD X,
11 months ago
Math,
11 months ago
English,
1 year ago