)A fox and an eagle lived at the top of a 6-meter-high cliff, at the foot of a cliff about 10 m away from
a point A on the ground. The fox descended from the cliff and went straight to point A. The eagle
jumps vertically to a height x meters and then flies in a straight line to point A, the distance traveled by
each is the same. Find the value of x.
Answers
x = 30/11 = 2.727 m or 6.5 m A fox and an eagle lived at the top of a 6-meter-high cliff
Step-by-step explanation:
Distance Covered by Fox = 6 + 10 = 16 m
Eagle jumps vertically to a height x meters and then flies in a straight line to point A
if jump is also calculated in Distance of eagle
Distance covered by Eagle = x + √10² + (6 + x)²
= x + √100 + 36 + x² + 12x
= x + √(x² + 12x + 136)
x + √(x² + 12x + 136) = 16
=> √(x² + 12x + 136) = 16 - x
Squaring both sides
=> x² + 12x + 136 = 256 + x² - 32x
=> 44x = 120
=> x = 120/44
=> x = 30/11 m
if jump is not calculated in Distance of eagle
√(x² + 12x + 136) = 16
Squaring both sides
=> x² + 12x + 136 = 256
=> x² + 12x -120 = 0
=> x ≈ 6.5 m
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