Math, asked by rudratubu, 2 months ago

(a)
Fox The building shown in fig 4.19 goccate
muss. The bunday has
The centre of
non unido
shown in the fiy
distribution of mass
cg
Ik lon x 20m

6m 14 km
um
losok
-
B В​

Answers

Answered by pathakshital780
0

Answer:

Since the top of the building is in the form of half of the cylinder of radius 3.5m, and length 10m, split along the diameter

V= volume of the godown

V= Volume of the cuboid +

2

1

(Volume of the cylinder of radius 3.5m and length 10m)

=(l×b×h)+

2

1

(πr

2

h)

={10×7×3+

2

1

(

7

22

×3.5×3.5×10)}m

3

=(210+192.5)m

3

=402.5m

3

total surface area excluding the base floor

=Area of four walls +

2

1

Curved surface area of the cylinder + 2 area of the semi-circles

=[2(10+7)×3×

2

1

(

7

22

×3.5×3.5×10)+2(

7

22

×3.5×3.5)]m

2

=250.5m

2

Similar questions