A fraction 9/11, if 2 is added to the both the numertor and denominotor if 3 is added to both the numertor and the denominotor it becomes 5/6 find the fraction
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Step-by-step explanation:
let numerator be x
denominator be y
x+2/y+2=9/11
11 (x+2)=9 (y+2)
11x+22=9y+18
11x+22-18=9y
11x+4=9y
11x-9y=-4 [1 eq^n ]
x+3/y+3=5/6
6 (x+3)=5 (y+3)
6x+18=5y+15
6x+18-15=5y
6x+3=5y
6x-5y=-3 [2 eq^n]
on solving eq^n 1 and 2
11x-9y=-4 (×6)
6x-5y=-3 (×11)
66x-54y=-24
66x-55y=-33
-y=-9
y=9
putting the value of y in eq^n 1
11x-9y=-4
11x-9×9=-4
11x-81=-4
11x=-4+81
11x=7
x=7/11
required fraction =x/y=7/99
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