A fraction become 1/3 when 1 is subtracted from the numerator and it becomes 1/4 when 8 is added to its denominator. Find the fraction.
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Let the fraction be x/y.
ATQ,
x-1/y = 1/3
=> 3x-3 = y
=> 3x-y = 3 ......(i)
&
x/y+8 = 1/4
=> 4x = y+8
=> 4x-y = 8 ......(ii)
By elimination method,
eqn.(ii)-eqn.(i)
=> (4x-y)-(3x-y) = 8-3
=> 4x-y-3x+y = 5
=> x = 5
On putting the value of x in eqn.(ii), we get-
(ii)=> 4×5-y = 8
=> 20-y = 8
=> y = 20-8
=> y = 12
So, the required fraction is 5/12.
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