a fraction becomes 1/3, if 2 is added to both numerator and denominator if if 3 is added to both numerator and denominator, it becomes 2/5 assuming the fraction to be [x/y], formulate two equations in two variables to represent the above problem
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let numerator be x and denominator be y.
according to question,
x + 2 / y + 2 = 1/ 3
= 3 ( x + 2 ) = y + 2
3x + 6 = y + 2
3x - y = 2 - 6
3x - y = - 4 - ( 1 )
second case :
x + 3 / y + 3 = 2 / 5
5 ( x + 3 ) = 2 ( y + 3 )
5x + 15 = 2y + 6
5x - 2y = 6 - 15
5x - 2y = - 9 - ( 2 )
using elimination method
multiply ( 1 ) by 5 and ( 2 ) by 3
= 5 ( 3x - y = - 4 )
15x - 5y = - 20 - ( 3 )
= 3 ( 5x - 2y = - 9 )
15x - 6y = - 27 - ( 4 )
subtract ( 3 ) and ( 4)
15x - 5y = - 20
15x - 6y = - 27
- + +
_______________
y = 7
_______________
put value of y in ( 1 )
3x - y = - 4
3x - 7 = - 4
3x = - 4 + 7
3x = 3
x = 3 / 3
x = 1
so, x = 1 and y = 7
I hope you understand.
please mark my answer as brainliest
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