Math, asked by KaushikLokesh, 11 months ago

A fraction becomes 1/3
when 1 is subtracted from the numerator and it
becomes 1/4
when 8 is added to its denominator. Find the fraction.​

Answers

Answered by vikram991
53

\bold{\underline{\red{Given:}}}

  • A fraction become 1/3 when 1 is subtracted from the numerator .
  • the fraction becomes 1/4 when 8 is added to its denominator .

\bold{\underline{\red{To \ Find :}}}

  • The fraction

\bold{\underline{\underline{\purple{Solution :}}}}

⇒Suppose the numerator be x

And, the denominator be y

According to First Condition of this Question :-

\implies \bold{\frac{x - 1}{y} = \frac{1}{3}}

\implies \boxed{\bold{y = 3x - 3}}.......1) Equation

According to Second Condition of this Question :-

\implies \bold{\frac{x}{y + 8} = \frac{1}{4}}

\implies \bold{y + 8 = 4x}

Now put value of y from Equation First :-

\implies \bold{ 3x - 3 + 8 = 4x}

\implies \boxed{\bold{ x = 5}}

Now Put value of x in First Equation :-

\implies \bold{ y = 3x - 3}

\implies \bold{ y = 3(5) - 3}

\implies \boxed{\bold{ y = 12}}

The Fraction = \bold{\dfrac{5}{12}}

\rule{200}2


StarrySoul: PERFECT! ♥️
Nereida: Awesome Viku !
Anonymous: Nice :)
Answered by StarrySoul
18

Given :

• Fraction becomes ⅓ when 1 is subtracted from the numerator. [1st Case]

• Fraction becomes ¼ when 8 is added to its denominator. [2nd Case]

To Find :

• Fraction.

Solution :

Let the numerator be x and denominator be y

 \sf \: Fraction =  \dfrac{x}{y}

According to 1st Case :

 \sf \longrightarrow \:  \dfrac{x -1 }{y}  =  \dfrac{1}{3}

 \sf \longrightarrow \:  3(x - 1) = y(1)

 \sf \longrightarrow \:  3x - 3 = y

 \sf \longrightarrow \:  3x  - y = 3

 \sf \longrightarrow \:  3x  =  3 + y

 \sf \longrightarrow \:  y  =  3x - 3....(i)

According to 2nd Case :

 \sf \longrightarrow \:  \dfrac{x }{y + 8}  =  \dfrac{1}{4}

 \sf \longrightarrow \:  4x =  y + 8

Put the value of y from equation i)

 \sf \longrightarrow \:  4x  = (3x-3) + 8

 \sf \longrightarrow \:  4x  = 3x-5

 \sf \longrightarrow \:  4x -3x = -5

 \sf \longrightarrow \:  -x = -5

 \sf \longrightarrow \red{ x = 5}

Put the value of x = 5 in equation i)

 \sf \longrightarrow \:  y  =  3x - 3

 \sf \longrightarrow \:  y  =  3(5) - 3

 \sf \longrightarrow \:  y  =  15 - 3

 \sf \longrightarrow \red{ y = 12}

Hence,

 \sf \boxed{\purple{\sf\: Fraction =  \dfrac{5}{12}}}


Nereida: Awesome :gift: !!
StarrySoul: Thank you Seno! ❣️
Anonymous: Perfect :)
StarrySoul: Thanks Wishes! :D
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