A fraction becomes 1/3 when 1 is subtracted from the numerator and it becomes 1/4 when 8 added to denominator
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Answered by
27
Heya !!!
Let numerator of fraction be X and denomination of fraction be Y.
Fraction = X/Y
According to Question,
X - 1 / Y = 1/3
3 ( X -1) = Y
3X - 3 = Y
3X - Y= 3 ------------(1)
And,
X / Y + 8 = 1/4
4X = Y + 8
4X - Y = 8 -------(2)
From equation (1) we get,
3X - Y = 3
3X = ( 3 + Y )
X = ( 3 + Y /3) --------(3)
Putting the value of X in equation (2)
4X - Y = 8
4 × ( 3 + Y /3) - Y = 8
12 + 4Y /3 - Y = 8
12 + 4Y - 3Y = 8 × 3
Y = 24 - 12
Y = 12
Putting the value of Y in equation (3)
X = ( 3 + Y /3) = ( 3 + 12/3)
X = ( 15/3) = 5
Fraction = X/ Y = 5/12
★ HOPE IT WILL HELP YOU ★
Let numerator of fraction be X and denomination of fraction be Y.
Fraction = X/Y
According to Question,
X - 1 / Y = 1/3
3 ( X -1) = Y
3X - 3 = Y
3X - Y= 3 ------------(1)
And,
X / Y + 8 = 1/4
4X = Y + 8
4X - Y = 8 -------(2)
From equation (1) we get,
3X - Y = 3
3X = ( 3 + Y )
X = ( 3 + Y /3) --------(3)
Putting the value of X in equation (2)
4X - Y = 8
4 × ( 3 + Y /3) - Y = 8
12 + 4Y /3 - Y = 8
12 + 4Y - 3Y = 8 × 3
Y = 24 - 12
Y = 12
Putting the value of Y in equation (3)
X = ( 3 + Y /3) = ( 3 + 12/3)
X = ( 15/3) = 5
Fraction = X/ Y = 5/12
★ HOPE IT WILL HELP YOU ★
Answered by
3
Let our Fraction is X/Y
so,
★our 1st equation will be (x-1)/y=1/3
★then our 2nd Equation according to the question will be X/y+8=1/4
Now we Have Both the equations
now you can solve it by any method such as Substitution,Elimination or Cross Multiplication...
so,
★our 1st equation will be (x-1)/y=1/3
★then our 2nd Equation according to the question will be X/y+8=1/4
Now we Have Both the equations
now you can solve it by any method such as Substitution,Elimination or Cross Multiplication...
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