Math, asked by tanishqjain95, 4 months ago

A fraction becomes 1/3 when l is subtracted from the numerator and it becomes 1/4 when &
is added to its denominator. The fraction obtained is
(a)3/12
(b)4/12
(c)5/12 (a)7/12​


kancharlabn: Let us assume thenumerator to be =x

Let us assume thedenominator to be =y

Hence the fractionbecomes=x/y

Accordingtothe given condition

(x−1)/y=1/3

⇒y=3x−3 ———-(i)

Accordingtothesecond givencondition,

x/(y+8)=1/4

⇒y+8=4x

⇒y=4x−8 ————(ii)

Combining(i)and(ii) we get,

3x−3=4x−8

⇒3x−4x=−8+3

−x=−5

⇒x=5

from(i)

y=15−3=12

So,the fraction is =5/12

Answers

Answered by S4MAEL
114

\underline\red{\bold{Answer :-}} (C) 5/12

\blue{\texttt{Given \: that :-}}

If 1 is subtracted from the numerator fraction becomes 1/4

firstly , let Numerator be x

& denominator be y

so , fraction is  \: \large\frac{x}{y}

Then,

 \large\frac{Numerator - 1}{Denominator}  =  \large\frac{1}{3}

 \frac{x - 1}{y}  =  \large\frac{1}{3}

3(x - 1) = y

3x - y =3 ____________(1)

Also, It 8 is added to denominator ,fraction becomes  \large\frac{1}{4}

 \large\frac{Numerator \: }{Denominator + 8}  =  \large\frac{1}{4}

 \large\frac{x}{y + 8}  =  \large\frac{1}{4}

4x  = y + 8

4x - y = 8 ___________(2)

\blue{\texttt{from \: (1) ,}}

3x - y = 3

3x = y  + 3

x = ( \large\frac{y + 3}{3})

\blue{\texttt{putting \: value \: of  \: x \:  in \: (2) ,}}

4x - y - 8 = 0

4 ( \large\frac{y + 3}{3})   - y - 8 = 0

multiplying both sides by 3 ,

3 \times 4x( \large\frac{y + 3}{3} ) - 3 \times y - 3 \times 8 = 3 \times 0

4(y + 3) - 3y - 24 = 0

4y + 12 - 3y - 24 = 0

y - 12 = 0

\underline\red{\bold{y \: = \: 12}}

\blue{\texttt{putting \: value \: of  \: y \: in \: equation \: (1) ,}}

3x - y = 3

3x - 12 = 3

3x = 12 + 3

3x =15

x =  \large\frac{15}{3}

\underline\red{\bold{x \: = \: 5}}

Therefore ,

\blue{\texttt{x \: = \: 5}}

\blue{\texttt{y \: = \: 12}} , is the solution.

so , \blue{\texttt{numerator \: = \: x \: = \: 5}}

\blue{\texttt{denominator \: = \: y \: = \: 12}}

original \: fraction \:  =  \large\frac{Numerator}{Denominator}  =  \frac{x}{y}

 =  \large\frac{5}{12}


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Answered by Anonymous
138

Answer:

Given :-

If 1 is subtracted from the numerator fraction becomes 1/4

To Find :-

Fraction

Solution :-

Let us assume the fraction be x/y

x-1/y = ⅓

By Cross Multiplication

3(x -1) = 1(y)

3(x - 1) = y

3x - y = 3 (1)

Now,

When 8 added

x/ y + 8 = ¼

4x - y + 8 (2)

From equation 1

3x - y = 3

3x = y + 3

x = y + 3/3

Now,

Putting x

4(y + 3/3) - y - 8 = 0

Now,

Multiplying LHS and RHS by 3

3 × 4x(y + 3/3) - 3 × y - 3 × 8 = 3 × 0

4x(y + 3/3) - 3 × y - 3 × 24 = 0

4x (y + 1) - 3 × y - 3 × 24 = 0

4( y + 3) - 3y - 24 = 0

4y + 12 - 3y - 24 = 0

4y - 3y - 24 - 12 = 0

y - 12 = 0

y = 12 + 0

y = 12

Now,

Finding x

3x - y = 3

3x - 12 = 3

3x = 12 + 3

3x = 15

x = 15/3

x = 5

Therefore :-

Fraction is 5/12.

 \\


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