Question

A fraction becomes 1/4 when 2 is subtracted from the numerator and 3 is added to the Denominator. Represent the situation as a linear equation in two variables. Also draw graph. ​

Answer 1

Answer:

X-2 = 1/4

Y+3

X-2 = Y/4 + 3/4 .ANS.

Step-by-step explanation:

Let the numerator be 'x' and the denominator be 'y'

Numerator = X-2

Denominator = Y+3

EQUATION :

=) X-2/Y+3 = 1/4

=) X-2 = Y/4 + 3/4 .ANS.

Refer to the Web for Graph  

MARK THE BRAINLIEST

Answer 2

$\large\underline{\sf{Solution-}}$

Let assume that

Numerator of a fraction = x

and

Denominator of a fraction = y

So,

According to statement,

When 2 is subtracted from the numerator and 3 is added to the denominator, the fraction becomes 1/4.

So,

Numerator of a fraction = x - 2

Denominator of the fraction = y + 3

So,

$\rm :\longmapsto\:\dfrac{x - 2}{y + 3} = \dfrac{1}{4}$

$\rm :\longmapsto\:4x - 8 = y + 3$

$\rm :\implies\:y = 4x - 11$

Substituting 'x = 0' in the given equation, we get

$\rm :\longmapsto\:\:y = 4(0) - 11$

$\rm :\longmapsto\:\:y = 0 - 11$

$\rm :\longmapsto\:\:y = - 11$

Substituting 'x = 1' in the given equation, we get

$\rm :\longmapsto\:\:y = 4(1) - 11$

$\rm :\longmapsto\:\:y = 4 - 11$

$\rm :\longmapsto\:\:y = - 7$

Substituting 'x = 2' in the given equation, we get

$\rm :\longmapsto\:\:y = 4(2) - 11$

$\rm :\longmapsto\:\:y = 8 - 11$

$\rm :\longmapsto\:\:y = - 3$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf - 11 \\ \\ \sf 1 & \sf - 7\\ \\ \sf 2 & \sf - 3 \end{array}} \\ \end{gathered}$

➢ Now draw a graph using the points.

➢ See the attachment graph.