A fraction becomes 9/11 if 2 is added to both numerator and denominator .if 3 is
added to both numerator and denominator it becomes 5/6. Find the fraction.
4
Answers
Step-by-step explanation:
Let the numerator and denominator be x and y respectively.
Therefore, the required fraction will be x/y
According to Question now,
➳ (x + 2)/(y + 2) = 9/11
➳ 11(x + 2) = 9(y + 2)
➳ 11x + 22 = 9y + 18
➳ 22 - 18 = 9y - 11x
➳ 4 = 9y - 11x
➳ 11x = 9y - 4
➳ x = 9y - 4/11.......[Equation (i)]
- Now, it is given that 3 is added to both numerator and denominator it becomes 5/6 :]
➳ (x + 3)/(y + 3) = 5/6
➳ (x + 3)6 = 5(y + 3)
➳ 6x + 18 = 5y + 15
➳ 6x - 5y + 18 - 15 = 0
➳ 6x - 5y + 3 = 0
➳ 6(9y - 4)/11 - 5y + 3 = 0
➳ 54y - 24/11 = 5y - 3
➳ 54y - 24 = 11(5y - 3)
➳ 54y - 24 = 55y - 33
➳ -24 + 33 = 55y - 54y
➳ 9 = y
Now, Putting y = 9 in equation (i) we get,
➳ x = 9y - 4/11
➳ x = 9(9) - 4/11
➳ x = 81 - 4/11
➳ x = 77/11
➳ x = 7
Therefore, the required fraction is 7/9.
Answer:
The fraction is 7/9.
Step-by-step explanation:
Given :-
- A fraction becomes 9/11 if 2 is added to both numerator and denominator.
- If 3 is added to both numerator and denominator it becomes 5/6.
To find :-
- The fraction.
Solution :-
Let the numerator of the fraction be x and the denominator of the fraction be y.
According to the 1st condition,
- A fraction becomes 9/11 if 2 is added to both numerator and denominator.
According to the 2nd condition ,
- If 3 is added to both numerator and denominator it becomes 5/6.
Two equations are :
- 11x-9y=-4...........(i)×6
- 6x-5y=-3............(ii)×11
By elimination,
66x-54y=-24
66x-55y = -33
(-). (+). (+)
_____________
y = 9
Now put y = 9 in eq(ii)
6x-5y=-3
→ 6x - 5×9 = -3
→ 6x = -3 + 45
→ x = 42/6
→ x = 7
Therefore,
- The fraction = 7/9