Question

A fraction becomes 9/11 if 2 is added to the nemorator and the denominator if 3 is added to both the numerator and the denominator is becomes 5/6 . find the fraction...please do not spam....​

Answer 1

$<font color= "multicolour">$Hey mate snswer of your question is given below by me..

Step-by-step explanation:

Let numerator be x

Let denomirator be y

Accordind to your question.....

x+2/y+2=9/11

11x+22=9y+18......equation first

11x-9y= 4.... equation second

x+3/y+3=5/6

6x+18=5y+15

6x-5=-3....

11x=-4+9

x= -4+9y/11

Putting the value of x in equation second...

6(-4+9y/11)-5y=-3

-24+54y/11-5y=-3

-24+5y-55/11=-3

-24-y=-3×11

-y=-33+24

-y=-9

y= -9/-1

y=9

.

We obtain value of y is 9

putting the value of y in equation first.

11x-9y=-4

11x-9×9=-4

11x-81=-4

11x=-4+81

x= 77/11

x=7

Value of x is 7...

So fraction is. ..x/y.

7/9

i hope it an help you..

Please mark as brainlist answer...

Answer 2

Answer:

Let the numerator and denominator be x and y respectively.

Therefore, the required fraction will be x/y

According to Question now,

➳ (x + 2)/(y + 2) = 9/11

➳ 11(x + 2) = 9(y + 2)

➳ 11x + 22 = 9y + 18

➳ 22 - 18 = 9y - 11x

➳ 4 = 9y - 11x

➳ 11x = 9y - 4

➳ x = 9y - 4/11.......[Equation (i)]

Now, it is given that 3 is added to both numerator and denominator it becomes 5/6 :]

➳ (x + 3)/(y + 3) = 5/6

➳ (x + 3)6 = 5(y + 3)

➳ 6x + 18 = 5y + 15

➳ 6x - 5y + 18 - 15 = 0

➳ 6x - 5y + 3 = 0

➳ 6(9y - 4)/11 - 5y + 3 = 0

➳ 54y - 24/11 = 5y - 3

➳ 54y - 24 = 11(5y - 3)

➳ 54y - 24 = 55y - 33

➳ -24 + 33 = 55y - 54y

➳ 9 = y

Now, Putting y = 9 in equation (i) we get,

➳ x = 9y - 4/11

➳ x = 9(9) - 4/11

➳ x = 81 - 4/11

➳ x = 77/11

➳ x = 7

Therefore, the required fraction is 7/9.