Question

a fraction bexome 8/11, if 3is added to both the numerator and the denominator also if 3 is. substracted from the numerator and the denominator it become 2/5 . find the fraction​

Answer 1

Answer:

let the numerator be x and denominator be y.

According to the question

x+3/y+3 = 8/11.

11(x+3) = 8(y+3)

11x+33=8y+24

11x-8y=-9. (1)

then, x-3/y-3 = 2/5

5(x-3) = 2(y-3)

5x-15 = 2y-6

5x-2y = 9. (2)

Multiplying 2nd equation to 4 gives

20x-8y = 36. (3)

(3) - (1) gives 9x= 45

X =45/9

x= 5

substitute x=5 in (2)

5(5)-2y = 9

25-2y = 9

-2y= 9-25

-2y = -16

y = 8

therefore the required fraction is 5/8