a fraction clutch is in the form of frastum of a cone the diameter of end being 32cm and 20cm and length 8cm.find the its bearing surface and volume.
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Question:- A fraction clutch is in the form of frastum of a cone the diameter of end being 32cm and 20cm and length 8cm.find the its bearing surface and volume.
Solution:- Here, a fraction clutch is in the form of frustum of a cone of diameter 32cm and 20cm and length 8cm.
Given,
D= 32 cm
So, R=D/2
=> R=32/2
=> R=16 cm
d = 20 cm
So, r= d/2
=> r= 20/2
=>r =10 cm
Volume of frustum of cone= 1/3πh(R^2 + r^2 + Rr)
=> 1/3 × 22/7 × 8[(10)^2+(16)^2+10×16]
=> 22/3 × 8/7(100+256+160)
=> 22/3 × 8/7(516)
=> 22/3 × 8/7 × 516
=> 22/3 × 589.71
=> 4,324.571 cm^3
Therefore, 4,324.571 cm^3 is its bearing surface and volume.
Solution:- Here, a fraction clutch is in the form of frustum of a cone of diameter 32cm and 20cm and length 8cm.
Given,
D= 32 cm
So, R=D/2
=> R=32/2
=> R=16 cm
d = 20 cm
So, r= d/2
=> r= 20/2
=>r =10 cm
Volume of frustum of cone= 1/3πh(R^2 + r^2 + Rr)
=> 1/3 × 22/7 × 8[(10)^2+(16)^2+10×16]
=> 22/3 × 8/7(100+256+160)
=> 22/3 × 8/7(516)
=> 22/3 × 8/7 × 516
=> 22/3 × 589.71
=> 4,324.571 cm^3
Therefore, 4,324.571 cm^3 is its bearing surface and volume.
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