A fraction is such that if the numerator is multiplied by 3 and the denominator is
reduced by 3, we get 3/2, but if the numerator is increased by 8 and denominator is
doubled, we get 5/7. Find the fraction.
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EXPLANATION.
- GIVEN
a fraction is such that the numerator is multiply
by = 3 and denominator is reduce by = 3
we get = 3/2
if the numerator is increased by = 8
denominator is double we get = 5/7
Find the fraction.
According to the question,
Let the fraction be = x/y
We get,
3x / y - 3 = 3/2 ......(1)
x + 8 / 2y = 5/7 .......(2)
From equation (1) and (2) we get,
=> 6x - 3y = -9 .....(1)
=> 7x - 10y = -56 .....(2)
From equation (1) and (2)
multiply equation (1) by 10
multiply equation (2) by 3
we get,
=> 60x - 30y = -90
=> 21x - 30y = -168
we get,
=> 39x = 78
=> x = 2
put the value of x = 2 in equation (1)
we get,
=> 6(2) - 3y = -9
=> 12 - 3y = -9
=> -3y = -21
=> y = 7
Therefore,
Fraction will be = x/y = 2/7
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