a framer moves a boundary of a square field of side 10 m 40 s. what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?
Answers
Answered by
2
Total time = 2×60 +20
= 140
If the farmer covers 40 m in 40 seconds then the farmer will be able to cover three full rounds and one
Half round of the sqaure field. (It can be shown through the figure)
Displacement will be of 1.414 m
= 140
If the farmer covers 40 m in 40 seconds then the farmer will be able to cover three full rounds and one
Half round of the sqaure field. (It can be shown through the figure)
Displacement will be of 1.414 m
Similar questions