Physics, asked by valsalasushma06, 5 months ago


A free electron is placed in a magnetic field of strength 1.3T. If g=2.0023 then the
resonance of the frequency is

(A) 36.43 Hz
(B) 36.43 kHz
(C) 36.43 MHz
(D) 36.43 GHz​

Answers

Answered by priyanshu302006
2

Answer:

a

Explanation:

  1. 36.43 Hz
Answered by prateekmishra16sl
0

Answer: Resonance frequency is 36.43  GHz

Explanation:

Resonance condition ⇒ hν = μBg

h ⇒ Plank's constant = 6.63 x 10⁻³⁴ Jsec

ν ⇒ Resonance frequency

B ⇒  Magnetic field

g ⇒  Land Splitting Factor ⇒  Ratio of magnetic moment of the electron to the total spin angular momentum of the electron.

μ ⇒ Bohr magneton = 9.27 × 10⁻²⁴  Am²

6.63 x 10⁻³⁴ × ν = 9.27 × 10⁻²⁴ × 1.3 × 2.0023

       ν       =   3.643 × 10¹⁰ Hz

       ν       =   36.43 × 10⁹ Hz

      ν       =   36.43  GHz

#SPJ3

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