A free electron is placed in a magnetic field of strength 1.3T. If g=2.0023 then the
resonance of the frequency is
(A) 36.43 Hz
(B) 36.43 kHz
(C) 36.43 MHz
(D) 36.43 GHz
Answers
Answered by
2
Answer:
a
Explanation:
- 36.43 Hz
Answered by
0
Answer: Resonance frequency is 36.43 GHz
Explanation:
Resonance condition ⇒ hν = μBg
h ⇒ Plank's constant = 6.63 x 10⁻³⁴ Jsec
ν ⇒ Resonance frequency
B ⇒ Magnetic field
g ⇒ Land Splitting Factor ⇒ Ratio of magnetic moment of the electron to the total spin angular momentum of the electron.
μ ⇒ Bohr magneton = 9.27 × 10⁻²⁴ Am²
6.63 x 10⁻³⁴ × ν = 9.27 × 10⁻²⁴ × 1.3 × 2.0023
ν = 3.643 × 10¹⁰ Hz
ν = 36.43 × 10⁹ Hz
ν = 36.43 GHz
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