A free falling body reaches the ground after 4s What is the height which it reaches?
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Answer:
as the body is falling freely so initial velocity is zero then by using second equation of motion,
S=gt²
S=(9.8)(4)²
S=156.8 m
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Given: A freely falling body reaches ground after 4 s.
To find: Height which it reaches
Explanation: Since the time taken to go up is equal to time taken in coming down, the time that the body took in coming down is 4/2= 2 s
At highest point, velocity (u)= 0
Using kinematic formula, Height= 1/2at^ 2
= 1/2* 10* 4
= 20 m
Also, the height that it comes down is equal to the maximum height that it reaches during its upward motion.
Therefore, the height that the body reaches is 20 m.
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